a/2)+1,6
a/2)+1,8
a/2)+2。</span><p align="justify"><font face="宋体"><span style="FONT-SIZE: 9pt; LINE-HEIGHT: 13pt"> 由于编号8的正三角形的边长是─+2,它与所设三角形ABC的边长a相等, 这样可求得a的值
a/2)+2=a,解得a=4。这样,六边形的周长为:</span><p align="center"><font face="宋体"><span style="FONT-SIZE: 9pt; LINE-HEIGHT: 13pt">a+(a+1)+(a+1)+(a+2)+((a/2)+1)+((a/2)+1)+((a/2)+2) =5(1/2)a+8=5(1/2)×4+8=30 </span><p align="justify"><font face="宋体"><span style="FONT-SIZE: 9pt; LINE-HEIGHT: 13pt">注:这道题通过"形"的组合,隐藏并反映:"数"的等量关系,找出等量关系后,使题目容易求解。</span></td></tr></table></div></td></tr></table>此帖由 江湖 在 2006-08-17 15:40 进行编辑...qqlmf+2006-08-18 17:19+pid944432-->引用: qqlmf @ 2006-08-18 17:19 [url=redirect.php?goto=findpost&p=944432">查看原帖[/url] 很想一阅谢谢
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yushi+2006-08-22 08:53+pid946622-->引用: yushi @ 2006-08-22 08:53 [url=redirect.php?goto=findpost&p=946622">查看原帖[/url] 想看看。。。
亦秋亦冬+2006-08-23 17:33+pid948535-->引用: 亦秋亦冬 @ 2006-08-23 17:33 [url=redirect.php?goto=findpost&p=948535">查看原帖[/url] 大大大大大大大大大大大大大大大大大大大大大大大大大大
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